c# GetFile, GetFilePreview

I use C# Appwrite 0.7 package, and I’m on Appwrite 1.14, I try to get a file from a bucket using

var storage = new Storage(client); File result = await storage.GetFile( bucketId: "[BUCKET_ID]", fileId: "[FILE_ID]");

it return the file in result, but I haven’t found the method to show it in picture box, I found some old doc using file.Content, but it doesn’t work anymore. After this I tried to get a preview using

var storage = new Storage(client); byte[] result = await storage.GetFilePreview( bucketId: "[BUCKET_ID]", fileId: "[FILE_ID]");

but this time, I get result=null, and it’s the same thing for: GetFileView, or GetFileDownload. Please help, I’m struggling, I would like to use GetFile and GetFilePreview, all the files are jpg images, and under 5mo. Thanks a lot

TL;DR

The user is trying to display an image from a bucket using the C# Appwrite 0.7 package. They have tried using the `GetFile` and `GetFilePreview` methods, but are encountering some issues. Solution: The user should check the following: 1. Make sure the `GetFile` method is returning a valid file by checking if `result` is null or not. 2. When accessing the content of the file, use `result.Content.Data` instead of `Encoding.UTF8.GetBytes(result.Content)`. 3. Ensure that the `GetFilePreview` method is returning a non-null value for `result

In general, how do you handle images in your tech stack?

before appwrite, i was using sql server, putting images directly in the db, now, i tried to use var storage = new Storage(client); File result = await storage.GetFile( bucketId: "[BUCKET_ID]", fileId: "[FILE_ID]"); byte[] file = Encoding.UTF8.GetBytes(result.Content); //here the problem, no content if (result != null) using (MemoryStream stream = new MemoryStream(file)) { Image image = Image.FromStream(stream); picDocument.Image = image; }

and with this : var storage = new Storage(client); byte[] result = await storage.GetFilePreview( bucketId: "[BUCKET_ID]", fileId: "[FILE_ID]"); if (result != null) //result is always null { Image image = Image.FromStream(stream); picDocument.Image = image; }